The logs rules work "backwards", so you can simplify ("compress"?) log expressions. When they tell you to "simplify" a log expression, this usually means they will have given you lots of log terms, each containing a simple argument, and they want you to combine everything into one log with a complicated argument. "Simplifying" in this context usually means the opposite of "expanding".
- Simplify log2(x) + log2(y).
Since these logs have the same base, the addition outside can be turned into multiplication inside:
log2(x) + log2(y) = log2(xy)
The answer is log2(xy).
- Simplify log3(4) – log3(5).
Since these logs have the same base, the subtraction outside can be turned into division inside:
log3(4) – log3(5) = log3(4/5)
The answer is log3(4/5).
- Simplify 2log3(x). Copyright © Elizabeth Stapel 2002-2011 All Rights Reserved
The multiplier out front can be taken inside as an exponent:
2log3(x) = log3(x2)
- Simplify 3log2(x) – 4log2(x + 3) + log2(y).
I will get rid of the multipliers by moving them inside as powers:
3log2(x) – 4log2(x + 3) + log2(y)
= log2(x3) – log2((x + 3)4) + log2(y)
Then I'll put the added terms together, and convert the addition to multiplication:
log2(x3) – log2((x + 3)4) + log2(y)
= log2(x3) + log2(y) – log2((x + 3)4)
= log2(x3y) – log2((x + 3)4)
Then I'll account for the subtracted term by combining it inside with division:
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